You need a 10% alcohol solution. on hand, you have a 80ml of a 95% alcohol mixture. how much pure water will you need to add to obtain the desired solution.

Let x be the amount of pure water (in mL) you need to add. The new mixture would have a total volume of 80+x mL. The solution you have contributes 0.95 mL of alcohol for each mL of solution, so that it currently contains 0.95*80 = 76 mL of alcohol. You want to the new mixture to have a concentration of 10%, so that

76 / (80 + x) = 0.1

==> 76 = 0.1(80 + x) = 8 + 0.1x

==> 68 = 0.1x

==> x = 680 mL

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation:

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3