The length of a rectangle is twice the width. the area is 392 yd². find the length and width.

L=28 yd

W=14 yd

Step-by-step explanation:

Here's what we know:

Length=L

Width=W

L*W=392 yards^2

L=2*W

We rewrite the equation to look like:

2W*W=392 yd^2

So, the simplified version of the new equation is 2W^2=392 yd^2

To find the answer, divide both sides by 2, and you'll find that W^2=196. To find W, simply take the square root of both sides and you'll find that W=14 yd

Now that you know what W is, you can plug it back into the equation for length.

L=2(14)

L=28 yd

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

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step-by-step explanation: