(a) what is wrong with the following equation? x2 + x − 2 x − 1 = x + 2 (x − 1)(x + 2) ≠ x2 + x − 2 the left-hand side is not defined for x = 0, but the right-hand side is. the left-hand side is not defined for x = 1, but the right-hand side is. none of these — the equation is correct. (b) in view of part (a), explain why the equation lim x → 1 x2 + x − 2 x − 1 = lim x → 1 (x + 2) is correct. since x2 + x − 2 x − 1 and x + 2 are both continuous, the equation follows. since the equation holds for all x ≠ 1, it follows that both sides of the equation approach the same limit as x → 1. this equation follows from the fact that the equation in part (a) is correct. none of these — the equation is not correct.