If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, it height in
feet after t second is given by y = 70t – 16t. find the average velocity for the time
period begining when t = 2 and lasting
(i) 0.1 seconds
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questions
► q 1 (0/1)
q 2 (0/1)
q3 (0/1)
q 4 (0/1)
q5 (0/1)
q 6 (0/1)
q7 (0/1)
q8 (0/1)
q 9 (0/1)
q 10 (0/1)
q 11 (0/1)
q 12 (0/1)
q 13 (0/1)
q 14 (0/1)
(ii) 0.01 seconds
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(iii) 0.001 seconds
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grade: 0/14
finally based on the above results, guess what the instantaneous velocity of the ball is
when t = 2.
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C. expression because any expression or equation may contain more than one variable

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )