Half the sum of 4 consecutive integers is 53 what are the integers?

25,26,27, and 28

Step-by-step explanation:

Write consecutive integers as x,x+1,x+2,x+3,x+4, and so forth.

x+x+1+x+2+x+3

      =   53

          2

1) Combine alike terms:

4x+6

  =    53

  2

2) Multiply both sides by 2:

4x+6=106

3) Subtract 6 from both sides:

4x=100

4) Divide both sides by 4:

x=25

5) Plug in 25 for x for all 4 integers:

25

26

27

28

40 x 50 = 2000

step-by-step explanation: