If you roll two number cubes, what is the probability of their sum being 9 or higher?

Step-by-step explanation:

Well, a standard cube number (dice) has numbers from 1 to 6. So the combinations that give 9 or higher, are 3-6, 6-3, 4-5, 5-4, 4-6, 6-4,5-6, 6-5, 5-5, 6-6. We will call this favorable cases (Fc) = 10

Yet, the total number of cases (T) is 6 different number by 6 different combinations (1-1 , 1-2 , 1-3 ..... 6-6), 6 x 6= 36 = T.

So, in order to calculate the probability of an event (10/36), you can use the following formula:

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step-by-step explanation: