What are the solutions to sin(2x)-cosx=0?

cos⁻¹0= 90°,270° or sin⁻¹1 =90°

step-by-step explanation:

from trigonometry sin (2x)=sinx × cosx

thus the equation becomes :

sinxcosx-cosx=0

factoring out cos x we get:

cosx(sin x-1)=0

therefore the roots are cos x and (sinx-1) either of which equals to 0.

cosx=0

sinx-1=0

thus sin x=1

cos⁻¹0= 90°,270° or sin⁻¹1 =90°