Eleanor and her little sister joanna are responsible for two chores on their family’s farm, gathering eggs and collecting milk. eleanor can gather 9 dozen eggs or collect 3 gallons of milk per week. joanna can gather 2 dozen eggs or collect 2 gallons of milk per week. a. the family wants 2 gallons of milk per week and as many eggs as the sisters can gather. currently, they gather one gallon of milk each and as many eggs as they can. how many dozens of eggs does the family have per week

4 dozens

Step-by-step explanation:

Find Eleanor and Joanna's ratio of eggs to milk

Eleanor:

Dozen eggs : gallons of milk

9 : 3

3 : 1

Joanna:

Dozen eggs : gallons of milk

2 : 2

1 : 1

They gather one gallon of milk each which means Joanna has 1 dozen eggs and Eleanor has 3 dozens of eggs.

Total dozen of eggs = 3 + 1 = 4

Therefore, total dozen of eggs the family have per week is 4 dozens.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

sine

step-by-step explanation: