Avan traveling at a speed of 32.0 mi/h needs a minimum of 42.0 ft to stop. if the same van is traveling 67.0 mi/h, determine its minimum stopping distance (in ft), assuming the same rate of acceleration. ft

Δx= 184.12 ft

Step-by-step explanation:

The equation you need to use is velocity as a function of displacement.

v = the speed at which the car is travelling,

and

v_o is the original speed (in this case zero).

The change in x (displacement) is how far the car travels. You will be solving for a (acceleration).

solving we get

a= 12.19

now put this acceleration value into the second case when v= 67mi/h

⇒Δx= 184.12 ft

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral