What are the possible values of x for the following functions?
f(x)= 3x/(x−1)(x−2)

all real numbers except the number 2 and number 1

Step-by-step explanation:

we have

we know that

In a quotient, the denominator cannot be equal to zero

so

Solve for x

The values of  x are

x=2, x=1

so

The domain of the function is all real numbers except the number 2 and number 1

In interval notation

(-∞,1) ∩ (1,2) ∩ (2,∞)

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.