Ineed ! don't solve work me through how to do this!
q: josiah had three less than twice as many nickels as dimes. if the total value of his coins was $1.45, how many of each kind of coin did he have?
this is for me to write and solve the equation that it is looking for!
78 !

13 nickels and 8 dimes

Step-by-step explanation:

okay, we know that he has $1.45

we know $1= 100 cents.

so we know he has 145 cents

we know one nickel= $0.05

we know one dime=$0.10

we know he has twice as many minuses 3 nickels compared to dimes.

with this information we can make an equation d=dimes n= nickels

145= (5x(n-3)) + (10xd)

we know whatever we plug in for n, d will be half as much. so plug in even numbers that can easily be decided by 2 for n. then take whatever number you put for n and divide it by 2 to get d. for example, if you put 10 for n you would put 5 for d.

eventually you'll end up with an equation that looks like this

145=(5×(16-3))-(10×8)

meaning you have

16-3= 13 nickels

and. 8 dimes

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )