If a projectile is launched vertically upward from the ground with an initial velocity of 70 ft per sec, neglecting air resistance, its height s (in feet) above the ground t seconds after projection is given by s equals negative 16 t squared plus 70 t. which equation should be used to determine the time at which the height of the projectile reaches 10 ft?

Step-by-step explanation:

Given that a projectile is launched vertically upward from the ground with an initial velocity of 70 ft per sec

Neglecting air resistance, its height s (in feet) above the ground t seconds after projection is given by

When height = 10 feet we have to find the time

Hence substitute s = 10 ft

We may get two answers as

The first time is for going up and the second is for coming down.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

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