Abird leaves its nest and travels 20 miles per hour downwind for x hours. on the return trip, the bird travels 4 miles per hour slower and has 6 miles left after x hours.
a. what is the distance of the entire trip?

b. how long does the entire trip take?

30 mi/ 24 mi (6 mi slower)

Step-by-step explanation:

distance = rate x time

distance = 20 mph * X hr = 20 X miles

return trip:

    distance = 16 mph * X hr + 6 miles = 16X + 6

They are the same:

 20X = 16X + 6

 4X = 6

 X = 6/4 = 3/2

20 mph * 3/2 hr = 30 miles.

On the return trip: 16 mph * 3/2 hr = 24 miles, which is 6 miles short of 30 mi.

The distance is 30 miles.

The bird flies all 30 miles in 3/2 hr = 1 and 1/2 hour = 1 hour 30 minutes.

On the return trip, the bird flies 24 miles in 1.5 hours, which is 6 miles short.

this is not the answer this is just a question. is this middle school math?

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.