Agraphing calculator is recommended. use the squeeze theorem to show that lim x → 0 (x2 cos(10πx)) = 0. illustrate by graphing the functions f(x) = −x2, g(x) = x2 cos(10πx), and h(x) = x2 on the same screen. let f(x) = −x2, g(x) = x2 cos(10πx), and h(x) = x2. then correct: your answer is correct. ≤ cos(10πx) ≤ correct: your answer is correct. ⇒ correct: your answer is correct. ≤ x2 cos(10πx) ≤ correct: your answer is correct. since lim x→0 f(x) = lim x→0 h(x) = , by the squeeze theorem we have lim x→0 g(x) =

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3