Consider a bag containing five red marbles, two green ones, one transparent one, four yellow ones, and two orange ones how many possible sets of five marbles are there in which none of them are red or green? sets need ? tente tutor

 21

Step-by-step explanation:

Given : A contains five red marbles, two green ones, one transparent one, four yellow ones, and two orange ones.

Total marbles =

Number of marbles except red or green =14-5-2=7

∵ Combinations of n things taken m at a time is given by :-

Now, the number of  possible sets of five marbles are there in which none of them are red or green :_

Hence, the number of  possible sets of five marbles are there in which none of them are red or green=21

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%