Show that a sequence {sn} coverages to a limit l if and only if the sequence {sn-l} coverages to zero.

Let be a sequence that converges to . This means for any , there is some such that for all . From this inequality we see that , so it follows that .

On the other hand, let be a sequence that converges to 0. This means for all large enough , and we get the simpler inequality for free, , so it follows that .

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

happy to

pls mark as brainliest

answer: i guess 5 units?

step-by-step explanation: