If a well was 70-feet deep, the frog climbs 7 feet per hour, and it slips back 2 feet while resting? how long (in hours) will it take for the frog to get out of the well?

14 hours

Step-by-step explanation:

Given well is 70 ft deep.

Each step of the climb involves moving up at 7 ft/hr and then slips down 2 feet. Assuming the frog rests only once each hour, then the resultant progress made each hour,

= distance climbed - distance lost by slipping

= 7 - 2

= 5 ft / hr

Hence we can say that :

5 feet ---> takes 1 hour

1 foot ---> takes 1/5 hours

70 feet ---> takes (1/5) x 70= 14 hours

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,