Aquadratic function is a function of the form y=ax^2+bx+c where a, b, and c are constants. given any 3 points in the plane, there is exactly one quadratic function whose graph contains these points. find the quadratic function whose graph contains the points (0, -2), (-5, -17), and (3, -17). enter the equation below. function: y = 0

y=-x²-2x-2

Step-by-step explanation:

Hey, just put x and y value to the statement and you will have 3 of them. Then solve the system :)

From 1st dot we see that c is -2, so a is -1 and b is -2. The result is:

y=-x²-2x-2

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.