Prove that the conjugate transpose of a matrix product is the product of the conjugate transposes in the opposite order, i. e., (ab)* = b'a . do this in general using indices, i. e., show that ((ab)*); k = (b*a") is using the definitions of conjugate transpose and matrix multiplication and properties of the conjugate.

500 dollars and its probably more than that

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: multiply exponents per exponent rules to get: remember you subtract exponents from the denominator and add exponents in the numerator so: simplify further: so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.