Aball is thrown upwards and it’s height h m, at time t s, is given by h=7t-4.9t2.how long does the ball spend more than 1.5m above ground?

 From what you wrote the I think the ball is drop

At time 0 you are 7 meters above ground

You basically just need to solve for

1.5 =7t-4.9t^2

by rearrange the equation you get

4.9t^2-7t+1.5=0

by using Quadratic Formula

t=1.166s

answer with step-by-step explanation:

a. ∠j is supplementary to ∠k - true:

(opposite angles of a trapezoid are supplementary which means that they add up to 180 degrees)

b. kl is parallel to jm - true:

(opposite sides are parallel to each other in a trapezoid)

c. jk is perpendicular to kl - false:

(clearly, jk does not make a right angle with kl)

d. jk is parallel to lm - false:

(jk and lm are two lines opposite in direction to each other so they cannot be parallel)

e. ∠j is congruent to ∠m - true:

(the angles on each side of the base are congruent)

f. ∠j is congruent to ∠k - false:

(the angles on the same side but opposite side of the base are not congruent)

tube or goog would be a great resource to with that question