Me!
question 1 (essay worth 10 points)
(01.02 mc)
part a: if (7^2)x = 1, what is the value of x? explain your answer. (5 points)
part b: if (7^0)x = 1, what are the possible values of x? explain your answer. (5 points)

Step-by-step explanation:

A.

(7^2)^x = 1

(49)^x = 1

thus x = 0

B.

(7^0)^x=1

(1)^x = 1

x can be any real number.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)