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Mathematics, 23.09.2019 04:10 janshnajdajdnnahjd

In ⊙h, arc i k ≅ arc j k, marc i k = (11x + 2)°, and marc j k = (12x – 7)°.what is the measure of arc i j k?

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Answer from: Quest

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

⭐⭐

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Answer from: Quest

pretty sure 750 each month!

step-by-step explanation:

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Answer from: Quest

can you put the picture up?

step-by-step explanation:

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Answer from: Quest

$\boxed{\bold{2240a^4u^{18}w^3x^4}}$

explanation:

remove parenthesis: $\bold{\left(a\right)=a,\: -\left(-a\right)=a}$

= $\bold{4u^9w^1\cdot \: 7x^4\cdot \: 4a^3w^2\cdot \: 8\cdot \frac{1}{2}a^1\cdot \: 5u^9}$

apply rule $\bold{a^1=a}$

= $\bold{4\cdot \: 7\cdot \: 4\cdot \: 8\cdot \: 5\cdot \frac{1}{2}a^3au^9u^9w^2wx^4}$

multiply fractions: $\bold{\: a\cdot \frac{b}{c}=\frac{a\: \cdot \: b}{c}}$

= $\bold{\frac{1\cdot \: 4u^9w\cdot \: 7x^4\cdot \: 4a^3w^2\cdot \: 8a\cdot \: 5u^9}{2}}$

$\bold{1\cdot \: 4u^9w\cdot \: 7x^4\cdot \: 4a^3w^2\cdot \: 8a\cdot \: 5u^9: \ 4480x^4w^3a^4u^{18}}$

= $\bold{\frac{4480a^4u^{18}w^3x^4}{2}}$

divide: $\bold{\frac{4480}{2}=2240}$

= $\bold{2240a^4u^{18}w^3x^4}$

mordancy.

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