Write the equation of a line that is parallel to y=1/2x−4y and that passes through the point (9,−6)

the desired equation is

y = (1/2)x - 21/2

Step-by-step explanation:

Looks as tho' you may have typed in an extra 'y' here.  I will proceed under the assumption that you meant y = (1/2)x - 4.  This line has a slope of 1/2.

Any line parallel to it also has a slope of m = 1/2.

Start by replacing y, x, m and b in y = mx + b with the knowns:

y = mx + b becomes -6 = (1/2)(9) + b.

Clear this of fractions by multiplying all 3 terms by 2:

-12 = 9 + 2b, or:

-21 = 2b.  Dividing both sides by 2 results in b = -21/2.

Thus, the desired equation is

y = (1/2)x - 21/2

-2

7 - 9 = -2

reversed:

-2 + 9 = 7

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm