Academic advising: in 2014, the community college survey of student engagement reported that 32% of the students surveyed rarely or never use academic advising services. suppose that in reality, 42% of community college students rarely or never use academic advising services at their college. in a simulation we select random samples from this population. for each sample we calculate the proportion who rarely or never use academic advising services. if we repeatedly obtain random samples of 200 students, what will be the mean and standard deviation of the sampling distribution of sample proportions?

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation:

are ya tryin to ask something or is this a statement