Apply the r-transform to the following characteristic equations of a discrete-data control system 2 3 2 ( .) 1.5 1 0 ( .) 2 0.5 0 i z z ii z z z        (a) determine the equivalent characteristic equations in r. (b) apply routh-hurwitz to determine how many roots of the characteristic equation are in the left half r-plane, in the right half r-plane, and on the imaginary axis. (c) use matlab or labview mathscript to determine the roots of the z and r characteristic equations and confirm your results in part (b). (use "roots" to solve for the root locations.)

the answer is 150.6

step-by-step explanation:

you multiply .02 by 30 and get .6.

and then you multiply 5.00 by 30 and get 150.

hope this !

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.

its a i did it myself

step-by-step explanation:

b.   e = 7.5h

hope this , lovely!