Abreath analyzer, used by the police to test whether drivers exceed the legal limit for blood alcohol percentage while driving, is known to satisfy p ( a | b ) = p ( a c | b c ) = p where a is the event "breath analyzer indicates that legal limit is exceeded" and b is the event "driver's blood alcohol percentage exceeds legal limit." on saturday night, about 5% of all drivers are known to exceed the limit. if we want p ( b | a ) to equal 0.9, what value of p should we use, rounded to 4 decimal places? group of answer choices

p = 0.9942

Step-by-step explanation:

By De Morgan's Law and using the fact that P is a probability

As on Saturday night, about 5% of all drivers are known to exceed the limit, P(B) = 0.05 and 1-P(B) = 0.95

We have then,

and

But

hence

P(A)+0.05-0.05p = 1-0.95p

and

P(A) = 0.95-0.9p

If we want P(B|A) = 0.9, then

and solving for p

0.05p = 0.855 - 081p

0.86p = 0.855

and finally

p = 0.9942

25.2

step-by-step explanation:

2+4x6-8/10= 25.2

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."