(merging of independent pps). let (n1(t))t≥0 and (n2(t))t≥0 be the counting processes of two independent pps of rates λ1 and λ2, respectively. define a new counting process (n(t))t≥0 by n(t) = n1(t)+ n2(t). (7) in this exercise, we show that (n(t))t≥0 ∼ pp(pλ). (i) let τ (1) k , τ (2) k , and τk be the kth inter-arrival times of the counting processes (n1(t))t≥0, (n2(t))t≥0, and (n(t))t≥0. show that τ1 = min(τ (1) 1 ,τ (2) 1 ). conclude that τ1 ∼ exp(λ1 +λ2).

594 square inches

step-by-step explanation:

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we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol