If two 6-sided number cubes are rolled, what is the probability that a 2 is rolled on the first cube and a 5 is rolled on the second cube?

There are 6 sides on the number cubes, numbered 1-6.

The odds of rolling a 2 are 1 in 6, or 1/6

P(2)=1/6

The odds of rolling a 5 are 1 in 6, or 1/6

P(5)=1/6

P(2)*P(5)=1/6*1/6=1/36

The odds of rolling a 2 and a 5 are 1/36

Answer=1/36

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1