Solve the equation for y.

(y-3)^2=4y-12

(y-3)²=4y-12

First we need to start by subtract 4y-12 from both sides

y²-6y+9-(4y-12)= 4y-12-(4y-12)

y²-10y+21=0

Now we need to do the factorization of the equation

we gonna factor the left side of it

(y-3)(y-7)=0

Set factors equal to 0

y-3=0 or y-7=0

y=3 or y=7

I hope that's help :0

hey there! : )

4y < -4

we need to isolate y. we can do this by simply dividing both sides by 4.

4y ÷ 4 > -4 ÷ 4

simplify.

y > -1

5 - y > 0

once again, we need to isolate y, so we can start off by subtracting 5 from both sides.

5 - y - 5 > 0 - 5

simplify.

-y > -5

divide both sides by -1.

** remember that when dividing any side by a negative, you must switch the sign! **

-y ÷ -1 < -5 ÷ -1

simplify.

y < 5

~hope i ! ~

the answer is  

d.

8 m

hope you got it down chief.