The width of a rectangular park is 23.4 yards. what is the perimeter of the park if the length is 2.5 times larger than the width.

163.8 yd

Step-by-step explanation:

The perimeter of a rectangle is twice the length added to twice the width.

The width is 23.4 yd.

The length is 2.5 times the width, so to find the length, we multiply the width by 2.5.

length = 2.5 * width = 2.5 * 23.4 yd = 58.5 yd

The length is 58.5 yd.

perimeter = 2 * length + 2 * width

perimeter = 2 * 58.5 yd + 2 * 23.4 yd

perimeter = 117 yd + 46.8 yd

perimeter = 163.8 yd

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-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

5.25 ounces

step-by-step explanation:

divided 3/4 and 6