Will mark brainliest and
square tuvw with vertices t(-6,1), u(-1,0), v(-2,-5), and w(-7,-4):
(a) reflection: in the y-axis (b) translation (x, y) —> (x-5,y+7)
a. (4,7)
b. (-5,7)
c. (1,0)
d. (-4,7)

Option D (-4,7)

Step-by-step explanation:

we have

Square TUVW with vertices T(-6,1), U(-1,0), V(-2,-5), and W(-7,-4

The question is

Find out the coordinates of U'

Part a) Reflection: in the y-axis

we know that

The rule of the reflection of a point across the y-axis is

(x,y) > (-x,y)

so

U(-1,0) > U'(1,0)

Part b) Translation (x,y) —> (x-5,y+7)

That means ---> the translation is 5 units at left and 7 units up

so

U'(1,0) > U''(1-5,0+7)

U'(1,0) > U''(-4,7)

therefore

Option D (-4,7)

option 1

data plot with   3 dots over 33, 1 dot over 34, 2 dots over 35, no dot over 36, 1 dot over 37, 2 dots over 38, 4 dots over 39, and 2 dot over 40.

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph