Use the quadratic polynomial x2+4 to answer the questions.
a: which summary correctly applies the fundamental theorem to the quadratic?
b: which statement correctly verifies the application of the fundamental theorem of algebra?
select one answer for question a, and select one answer for question b.
a: this polynomial has a degree of 2, so the quadratic equation x2+4=0 has two or fewer roots.
b: the quadratic equation x2+4=0 has three solutions, x=−2i, x=2i, or x=0, and therefore has three roots.
a: this polynomial has a degree of 2, so the quadratic equation x2+4=0 has more than two roots.
b: the quadratic equation x2+4=0 has two complex solutions, x=−2i or x=2i, and therefore has two complex roots.
a: this polynomial has a degree of 2, so the quadratic equation x2+4=0 has exactly two roots.
b: the quadratic equation x2+4=0 has one complex solution, x=−2i, and therefore has one complex root with a multiplicity of 2.

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step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

i belive the biggest ratio would be 18: correct me if im wrong

2 equivalent expressions to represent the area of a rectangle and the top is n-3 and the side is 2

area of the rectangle = length * width

given length = n - 3

width = 2

replace it in the area

so area of the rectangle = (n-3) *2

= 2(n-3)

one of the expression is 2(n-3)

to get another expression we distribute 2 inside the parenthesis

2(n-3) is 2n - 6

so another expression is 2n - 6

two equivalent expression are

2(n - 3)   , 2n - 6