How many distinct arrangements can be formed from all the letters of "students"? show your work.
a) 10,080
b) 40,320
c) 1680
d) 720

There are a total of 8 letters in student, with 6 different letters ( there are 2 s's and 2 t's).

First find the number of arrangements that can be made using 8 letters.

This is 8! which is:

8 x 7 x 6 x 5 x 4 3 x 2 x 1 = 40,320

Now there are 2 s's and 2 t's find the number of arrangements of those:

S = 2! = 2 x 1 = 2

T = 2! = 2 x 1 = 2

Now divide the total combinations by the product of the s and t's:

40,320 / (2*2)

= 40320 / 4

= 10,080

The answer is A. 10,080

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3