Mike rented a car. he drove 30 miles and the fee was $22.50. ben rented a car from the same establishment . he drove 50 miles and his fee was $31.50 how much does it cost to travel 7 miles in a cab?

Step-by-step explanation:

For this problem, the cost for renting a car is based on a flat rate of $/mile

You need to know that the rate = cost/distance  

(a)  That expression can be rearranged by multiplying both sides by distance:  rate • distance = cost

The cost (y) =  the rate ($/mile) times the distance driven (x):   y ($) = rate ($/mi) • x (mi) with the units in ( )

You are given information to calculate the rate for two drivers:

For Mike, x = 30 miles and the cost = $22.50, and rate = cost/distance

                                                                            rate = $22.50 / 30 miles  =  $0.75/mile

For Ben, x = 50 miles and the cost is $31.50;  rate = $31.50 / 50 miles = $0.63

Ben pays a lower rate than Mike.

(b) for Mike's travel:

      rearrange the equation cost =  rate • distance to solve for distance by dividing both sides by rate:

      cost / rate = distance • rate / rate  

      rewriting, distance = cost / rate = $21.00/($0.75/mile) = 28 miles

(c) You may have missed part of this question.  Parts (c) and (d) questions make no sense since there is no information given for a "cab".

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

c) yes, because of asa or aas