Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of startfraction one-third endfraction.? y + 2 =y plus 2 equals startfraction one-third endfraction left-parenthesis x plus 3 right-parenthesis.(x + 3) y – 2 = y minus 2 equals startfraction one-third endfraction left-parenthesis x minus 3 right-parenthesis.(x – 3) y + 3 = y plus 3 equals startfraction one-third endfraction left-parenthesis x plus 2 right-parenthesis.(x + 2) y – 3 = y minus 3 equals startfraction one-third endfraction left-parenthesis x minus 2 right-parenthesis.(x – 2)

We want to find the equation of a line in the point-slope form, such that we know the slope and a point on the line.

The line will be: y - 2 = (1/3)*(x - 3)

Let's see how to find that line:

We know that our line has a slope equal to 1/3, and that it passes through the point (3, 2).

First, a general line in the point-slope form is:

y - y₁ = a*(x - x₁)

Where a is the slope and (x₁, y₁) is the point on the line.

Then, by using that general form and the given information, we can see that our line is:

y - 2 = (1/3)*(x - 3)

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y - 2 = (x - 3)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = and (a, b) = (3, 2), thus

y - 2 = (x - 3) ← in point- slope form

mental cunning

explanation:

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180

step-by-step explanation: