The length of a rectangular frame is represented by the expression 2x+4 and the width of the rectangular frame is represented by the expression 2x+10. write an equation to solve for the width of a rectangular frame that has a total area of 120 square inches
2x^2+20x-80=0
4x^2+28x+40=0
4x^2+28x-80=0
x^2+8x+20=0

4x^2 + 28x - 80=0

Step-by-step explanation:

(2x+4)(2x+10) = 120

1. Use FOIL (Distribute):

4x^2 + 20x +8x + 40 = 120

2. Group like terms:

4x^2 + 28x+ 40 = 120

3. Subtract 120 from both sides:

4x^2 + 28x - 80 = 0

Option 3 -

Step-by-step explanation:

We have given,

The length of a rectangular frame is represented by the expression L=2x+4.

The width of the rectangular frame is represented by the expression B=2x+10.

The total area of a rectangular frame is A=120 square inches.

To find : Write an equation to solve for the width of a rectangular frame ?

Solution :

The area of the rectangle is given by,

Substitute the values,

The required equation is

Therefore, option 3 is correct.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116