The lengths of the sides of a triangle are 3, 3, 3 square root 2 can the triangle be a right triangle?

Step-by-step explanation:

If the base and height were each 3, then the hypotenuse would need to be:

3^2 + 3^2 = C^2

9 + 9 = C^2

18 = C^2

C = SQRT(18) = 4.24

This is larger than sqrt(3), so this cannot be a right triangle.

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