An electret is similar to a magnet, but rather than being permanently magnetized, it has a permanent electric dipole moment. suppose a small electret with electric dipole moment 1.0 × 10−7 cm is 25 cm from a small ball charged to + 80 nc, with the ball on the axis of the electric dipole.

In this question, we need to find the magnitude of the electric force on the ball; the answer is N.

Step-by-step explanation:

To resolve this question, we're going to need E= that is the magnitude of an electric field in the axis of a dipole at some distance "r" .

where "p" is the magnitude of the electric dipole moment, so in this case p= 1.0 Cm or what is the same cm; and k is a constant k value is =

now to get the force on the ball we need to use F=qE where

so we have

for this, "q" is the charge on the ball, so we got 80nC or what si the same 80×C, and r is the distance between the ball and the dipole, r= 25cm= 0.25m (1m=100cm, so we need to divide 25cm into 100 to get it in meters)

Replacing we got:

F=(80×)(8.99×)(2()) /

and calculating this the answer is

hi there! my name is zalgo and i am here to you out today. the answer is pretty simple (in a way). this equation equals to 25.2!

i hope this answer !

"stay and stay proud! " - zalgo