Mathematics, 26.09.2019 21:30 michaelmcgee99
Given: ∆abc, ∆a1b1c1, ab = a1b1 ac = a1c1, m∠a = m∠a1 p∈ ab , p1 ∈ a1b1 , ap = a1p1 prove: △bpc≅ △b1p1c1
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Given: ∆abc, ∆a1b1c1, ab = a1b1 ac = a1c1, m∠a = m∠a1 p∈ ab , p1 ∈ a1b1 , ap = a1p1 prove: △bp...
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