What is the vertex and axis of symmetry of f(x) = (x + 3)(x + 5)?

a vertex (-4, -1) & axis of symmetry x = -1

b vertex (-4, -1) & axis of symmetry x = -4

c vertex (4, 1) & axis of symmetry x = 4

d vertex (-4, 1) & axis of symmetry x = -4

need on this

If you expand y=(x+3)(x+5)
You get: f(x)= x^2+8x+15

A=1 b=8 C=15

To find x-coordinate of vertex:
use formula -b/2a
-8/2(1)= -4 this is x coordinate

To find y coordinate plug the x value in original equation.

F(-4) = (-4+3)(-4+5)
F(-4) = (-1)(1)
F(-4) = -1

Vertex is (-4, -1)

And x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.

Axis of symmetry is -4

Option B is answer

Answer: 10pi

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

She’s has 59 assignments to contaminate