Lila collected the honey from 3 of her beehives. from the first hive she collected 2/3 gallon of honey. the last two hives yielded 1/4 gallon each.
a. how many gallons of honey did lila collect in all? draw a diagram to support your answer.
b. after using some of the honey she collected for baking, lila found that she only had 3/4 gallon of honey left. how much honey did she use for baking? support your answer using a diagram, numbers, and words.
c. with the remaining 3/4 gallon of honey, lila decided to bake some loaves of bread and several batches of cookies for her school bake sale. the bread needed 1/6 gallon of honey and the cookies needed 1/4 gallon. how much honey was left over? support your answer using a diagram, numbers, and words.
d. lila decided to make more baked goods for the bake sale. she used 1/8 lb less flour to make bread than to make cookies. she used 1/4 lb more flour to make cookies than to make brownies. if she used 1/2 lb of flour to make the bread, how much flour did she use to make the brownies? explain your answer using a diagram, numbers, and words.

a). Lila collected 7/6 gallon in all.

b). She used for baking 5/12 gallon.

c) was left 1/3 gallon of honey

D) She used 3/8lb flour to make the brownies.

Step-by-step explanation:

a). Lila collected 7/6 gallon in all.

LCM=3*4=12

b). She used for baking 5/12 gallon.

She had 7/6 gallon of honey. She used 3/4 gallon for baking. To know how much honey was left, you have to substract 3/4 gallon from the total available honey 7/6 gallon.

You need to find LCM to substract fractions with different denominator:

LCM=12

c) was left 1/3 gallon of honey

To know how much honey was left you need to substract from the initial quantity of honey that is 3/4 gallon, the quantities used for baking, that are 1/6 gallon and 1/4 gallon.

Less common multiple: 12

We use LCM 12 to substract:

D) She used 3/8lb flour to make the brownies.

You know she used 1/2 lb flour to make the bread and to make cookies 1/8 more. So you need to do following math:

d)

She used 5/8 to make cookies and she used 1/4 more to make cookies than brownies, then you have to do following math;

The total amount of honey in gallons did Lila collect is 7/6 gallons, the amount of honey in gallons she uses for baking is 5/12 gallons, the honey left after baking some loaves of bread and several batches of cookies is 1/3 gallons, and 3/8 lb of flour she uses to make the brownies.

Given :

A) Total amount of honey in gallons did Lila collect in all:

B) The amount of honey in gallons she uses for baking will be:

C) The honey left after baking some loaves of bread and several batches of cookies will be:

D)  Lila used 1/2 lb flour to make the bread and to make cookies 1/8 more.

Lila used 5/8 to make cookies and she used 1/4 more to make cookies than brownies.

3/8 lb flour she use to make the brownies.

For more information, refer to the link given below:

link

answer:  

123455421

step-by-step explanation: easy

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!