Two rectangular prisms have a combined volume of 432 cubic feet. prism a has half the volume of prism b.
a. what is the volume of prism a? prism b?
b. if prism a has a base area of 24 ft², what is the height of prism a?
c. if prism b’s base is 2/3 the area of prism a’s base, what is the height of prism b?

a. 144 cubic foot

b. 12 ft

c. 18 ft

Step-by-step explanation:

Let the volume of prism A be V_a

and that of prism b be V_b

ATQ,   V_a  +  V_b= 432

also V_a= 0.5 V_b

⇒1.5 V_b= 432

= V_b= 432/1.5= 288 cubic feet

therefore V_a= 144  cubic feet

volume of prism= area of base×height = V_a

24×h = 144

⇒h= 12 ft

A_b= 2/3×24

⇒base area of prism B= 16 sq.ft

now 16×h_b= 288⇒h_b= 288/16= 18 ft

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !