One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides of the same square. find the side of the triangle if the side of the square is 10 ft.

The side of the triangle is either 38.63ft or 10.35ft

This problem can be translated as an image as shown in the Figure below. We know that:

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

Therefore, for Triangle 3, we have that by Pythagorean theorem:

Matching equations (1) and (2):

Using quadratic formula:

Finding x from (1):

Finally, the side of the triangle is either 38.63ft or 10.35ft

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.

where did you get them? if you picked from the grass, is is probably poisonous.

step-by-step explanation: