Assume that the hands of a clock move continuously across its face. what are the times, if any, between 4 and 5 p. m. at which its hands form an angle of 144°?

At  4:48 p.m.

Step-by-step explanation:

angle between hands of the clock is given by

θ= | 30H- 11/2M |

Where H and M are hours and minutes respectively.

H=4

θ= | 30×4- 11/2M |

⇒144°= | 120- 11/2M |

solving Above equation we get M= 48 minutes

Time = 4:48 p.m.

therefore between 4 and 5 p.m. at  4:48 p.m. the angle between minute and hour hand is 144°

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632