Mathematics, 29.09.2019 05:30 megs87
Starting with (a7), and using only elementary row operations, find the inverse of a = 12 1 1) 1 2 1 1 1 2) again, you'll be graded on the correct execution of eros
Answers: 1
![A^{-1}=\left[\begin{array}{ccc}3/4&-1/4&-1/4\\-1/4&3/4&-1/4\\-1/4&-1/4&3/4\end{array}\right]](/tpl/images/0272/9478/0a2d3.png)
![A=\left[\begin{array}{ccc}2&1&1\\1&2&1\\1&1&2\end{array}\right]](/tpl/images/0272/9478/fa57e.png)
![\left[\begin{array}{ccc|ccc}2&1&1&1&0&0\\1&2&1&0&1&0\\1&1&2&0&0&1\end{array}\right]](/tpl/images/0272/9478/dbf17.png)
![\left[\begin{array}{ccc|ccc}1&1/2&1/2&1/2&0&0\\1&2&1&0&1&0\\1&1&2&0&0&1\end{array}\right]](/tpl/images/0272/9478/3240b.png)
![\left[\begin{array}{ccc|ccc}1&1/2&1/2&1/2&0&0\\0&3/2&1/2&-1/2&1&0\\1&1&2&0&0&1\end{array}\right]](/tpl/images/0272/9478/bda02.png)
![\left[\begin{array}{ccc|ccc}1&1/2&1/2&1/2&0&0\\0&3/2&1/2&-1/2&1&0\\0&1/2&3/2&-1/2&0&1\end{array}\right]](/tpl/images/0272/9478/352a6.png)
![\left[\begin{array}{ccc|ccc}1&1/2&1/2&1/2&0&0\\0&1&1/3&-1/3&2/3&0\\0&1/2&3/2&-1/2&0&1\end{array}\right]](/tpl/images/0272/9478/6d528.png)
![\left[\begin{array}{ccc|ccc}1&1/2&1/2&1/2&0&0\\0&1&1/3&-1/3&2/3&0\\0&0&4/3&-1/3&-1/3&1\end{array}\right]](/tpl/images/0272/9478/cec99.png)
![\left[\begin{array}{ccc|ccc}1&1/2&1/2&1/2&0&0\\0&1&1/3&-1/3&2/3&0\\0&0&1&-1/4&-1/4&3/4\end{array}\right]](/tpl/images/0272/9478/997d6.png)
![\left[\begin{array}{ccc|ccc}1&1/2&1/2&1/2&0&0\\0&1&0&-1/4&3/4&-1/4\\0&0&1&-1/4&-1/4&3/4\end{array}\right]](/tpl/images/0272/9478/589ac.png)
![\left[\begin{array}{ccc|ccc}1&1/2&0&5/8&1/8&-3/8\\0&1&0&-1/4&3/4&-1/4\\0&0&1&-1/4&-1/4&3/4\end{array}\right]](/tpl/images/0272/9478/ebb35.png)
![\left[\begin{array}{ccc|ccc}1&0&0&3/4&-1/4&-1/4\\0&1&0&-1/4&3/4&-1/4\\0&0&1&-1/4&-1/4&3/4\end{array}\right]](/tpl/images/0272/9478/e4207.png)
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Starting with (a7), and using only elementary row operations, find the inverse of a = 12 1 1) 1 2 1...
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