Hey, can you factor completely 6x^2+11x-10 as (6x-4)(x-15/6)?

i know the proper way is (3x−2)(2x+5) but i did it this way and want to know if it is correct.

The answer to your question is below

Step-by-step explanation:

Factor completely                          6x² + 11x - 10

1.- Multiply 6 by -10 = -60

2.- Find the prime factors of -60

       -60     2

       -30     2

       -15      3                60 = 2 x 2 x 3 x 5

       -5        5              Combine these numbers so, if add them up give +11

       -1                          and if multiply equals -60.

                                   These numbers are +15 and -4

                                    Instead of writing +11x, in the original equation, write,                

                                    + 15x - 4x.

                                    6x² - 4x + 15x - 10       Factorize like terms

                                    2x(3x - 2) + 5(3x - 2)   Factorize like terms

                                    (3x - 2) (2x + 5).

Sorry, I could not get (6x - 4) (x - 15/6)

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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