The length of a rectangle is 10 ft longer than twice the width. if the perimeter is 68 ft, find the length and width of the rectangle.

me

w=8; l=26 ft.

Step-by-step explanation:

1. according to the condition the phrase 'the length is 10 longer than 2 the width' means length=2*width+10;

2. according to the condition the perimeter is p=68;

3. the formula of the perimeter of the given rectangle is p=2(length+width);

4. after substitution into the formula (3) expression for the length (1):

perimeter=2(2*width+10+width); ⇔ perimeter=2*(3*width+10);

5. if to substitute perimeter=68, then 2*(3width+10)=68; ⇒ width=8 ft.

6. according to the (1) the length is 2*8+10=26 ft.