Super urgent
a, b, and c are collinear, and b is between a and c. the ratio of ab to bc is 1: 2. if a is at (7,-1) and b is at (2,1) what are the coordinates of point c

hope it is correct and sorry for handwriting... if it is not correct please forgive me...

  C = (-8, 5)

Step-by-step explanation:

You are given that ...

  (B-A) : (C-B) = 1 : 2 . . . . . . the required relationship between A, B, and C

  2(B -A) = C - B . . . . . . . . . "cross multiply" . . . p:q = r:s ⇒ ps = qr

  3B -2A = C . . . . . . . . . . . . add B

  C = 3(2, 1) -2(7, -1) = (6-14, 3+2) . . . . . substitute the given coordinates

  C = (-8, 5)

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.