An instructor in a large lecture class found, at the end of the semester, that the total point distribution in his class was approximately normal, with a mean of 530 and a standard deviation of 80. if 10% of the class is to receive a’s (the instructor grades on a curve), what is the lowest number of points that a student can have and still earn an a?

The lowest number of points that a student can have and still earn an A is 632.

Step-by-step explanation:

Since we have given that

Mean = 530

Standard deviation = 80

If 10% of the class is to receive A's, then we need to find the lowest number of points that a student can have and still earn an A.

Let X be the number of points.

so,

so, it becomes,

From the Z-table, we get that

So, we get that

Hence, the lowest number of points that a student can have and still earn an A is 632.

57 732

step-by-step explanation:

i dont really.know

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)