The commuting time for a student to travel from home to a college campus is normally distributed with a mean of 30 minutes and a standard deviation of 5 minutes. if the student leaves home at 8: 25 a. m., what is the probability that the student will arrive at the college campus later than 9 a. m.?

0.1587

Step-by-step explanation:

Let X be the commuting time for the student. We know that . Then, the normal probability density function for the random variable X is given by

. We are seeking the probability P(X>35) because the student leaves home at 8:25 A.M., we want to know the probability that the student will arrive at the college campus later than 9 A.M. and between 8:25 A.M. and 9 A.M. there are 35 minutes of difference. So,

= 0.1587

To find this probability you can use either a table from a book or a programming language. We have used the R statistical programming language an the instruction pnorm(35, mean = 30, sd = 5, lower.tail = F)

the answer is 48m^2!

step-by-step explanation:

i believe it's a.

i'm not sure on this one, most likely correct.